10[z-(10z+16)+7]=3(z+1)

Solution for 10[z-(10z+16)+7]=3(z+1) equation:

Simplifying
10[z + -1(10z + 16) + 7] = 3(z + 1)

Reorder the terms:
10[z + -1(16 + 10z) + 7] = 3(z + 1)
10[z + (16 * -1 + 10z * -1) + 7] = 3(z + 1)
10[z + (-16 + -10z) + 7] = 3(z + 1)

Reorder the terms:
10[-16 + 7 + z + -10z] = 3(z + 1)

Combine like terms: -16 + 7 = -9
10[-9 + z + -10z] = 3(z + 1)

Combine like terms: z + -10z = -9z
10[-9 + -9z] = 3(z + 1)
[-9 * 10 + -9z * 10] = 3(z + 1)
[-90 + -90z] = 3(z + 1)

Reorder the terms:
-90 + -90z = 3(1 + z)
-90 + -90z = (1 * 3 + z * 3)
-90 + -90z = (3 + 3z)

Solving
-90 + -90z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-90 + -90z + -3z = 3 + 3z + -3z

Combine like terms: -90z + -3z = -93z
-90 + -93z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-90 + -93z = 3 + 0
-90 + -93z = 3

Add '90' to each side of the equation.
-90 + 90 + -93z = 3 + 90

Combine like terms: -90 + 90 = 0
0 + -93z = 3 + 90
-93z = 3 + 90

Combine like terms: 3 + 90 = 93
-93z = 93

Divide each side by '-93'.
z = -1

Simplifying
z = -1